State the universal law of gravitation. From the equation (1) and (2), we get = 0 – (0.5)2 = 2 × (-9.8) × h Gravitation Multiple Choice Questions & Answers for competitive exams. (i) We know v2 – u2 How does the force of attraction between the two bodies depend upon their masses and distance between them? Answer According to question, M S = Mass of the Sun = 2×10 30 kg M E = Mass of the Earth = 6×10 24 kg R = Average distance between the Earth and the Sun = 1.5×10 11 m From Universal law of gravitation, The acceleration produced in the motion of a body falling under the force of gravity is called acceleration due to gravity. So, the earth does not fall into the sun. Find out the ratio of time they would take in reaching the ground. Observe the graph and answer the following questions. Question 2. Question 4. Find the percentage change in the weight of a body when it is taken from the equator to the poles. (ii) As v = u2 + 2 gs Answer: (d) The quantity G is universal constant of nature. Balbharati solutions for Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 (Gravitation) include all questions with solution and detail explanation. Question 3. ⇒ t = $$\sqrt{10}$$ = 3.16 s Isaac Newton. For the first stone or, v = $$\sqrt{800}$$ The acceleration due to gravity is more at the poles than at the equator. Answer: mg = $$G \frac{m M}{R^{2}}$$ or g = $$\frac{G M}{R^{2}}$$ …(3) The ratio of their accelerations due to gravity at the surface is (R 1 /R 2) 2 (R 2 /R 1) 2 ... Click the "Score and Show Answer(s)" button for explanations. The entire NCERT textbook questions have been solved by best teachers for you. It is applied to all the body present in universe It is constant of proportionality in Newton’s universal law of gravitation. Question 9. Show that the weight of an object on the moon is $$\frac{1}{6}$$ th of its weight on the earth. So, both the stones will reach the ground at the same time when dropped simultaneously. This force depends on the product of the masses of the planet and sun and the distance between them. 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Answer: Answer: Answer: Velocity-time graph for the ball’s motion is shown in figure. ⇒ Average density of the earth, D = $$\frac{\text { Mass }}{\text { Volume }}=\frac{g R^{2}}{G \times V e}$$ Answer: Question 5. From a cliff of 49 m high, a man drops a stone. Answer: Weight of a body ∝ $$\frac{M}{R^{2}}$$ 1. The radius of the earth is 6400 km and g = 10 m/s². Question 2. Answer: Calculate the height of the building. (ii) Weight = $$\frac{G M m}{r^{2}}$$, where r is the radius of the earth. Gravitation Class 11 MCQs Questions with Answers. Browse from thousands of Gravitation questions and answers (Q&A). Derive an expression for acceleration due to gravity in terms of mass of the earth (M) and universal gravitational constant (G). If the small and big stones are dropped from the roof of a house simultaneously, they will reach the ground at the same time. u = 0 ms-1, h = 49 m, On the moon’s surface, the acceleration due to gravity is 1.67 ms-2. So, when dropped from the same height a body reaches the ground quicker at the poles than at the equator. The earth is acted upon by gravitation of sun, even though it does not fall into the sun. Q.17 Does the gravitational force same for two objects inside and outside the water? Answer: According to Newton’s third law of motion, action and reaction are equal and opposite. As the body falls back to the earth with the same velocity it was thrown vertically upwards. Since, the two forces, i.e., Fp and FQ are equal, thus from (1) and (2), 1. Does the apple also attract the earth? Question 4. Let P and Q be the two bodies, Why? F ∝ m,1m2 and F ∝ $$\frac{1}{r^{2}}$$ Why does formation of tides takes place in sea or ocean? $$\frac{W_{m}}{W_{e}}=\frac{M_{m}}{M_{e}} \times \frac{R_{e}^{2}}{R_{m}^{2}}$$ …. F = $$G \frac{m M}{R^{2}}$$ …..(1) [NCERT Exemplar] Find the position of that point. When a body is dropped from a height, what is its initial velocity? When r changes to 2r, the new weight is given by The standard kilogram is the mass of a block of a platinum alloy kept at the international bureau of weights and measures near Paris in France. Original weight, W0 = mg = mG $$\frac{M}{R^{2}}$$ ∴ v = 0 + (-10) × 2 = -20 ms-1 Yes, fluids have weight. It means that the force on the apple due to earth’s attraction is equal to that on the earth due to apple’s attraction. We know that g = $$\frac{G M}{R^{2}}$$ or M = $$\frac{g R^{2}}{G}$$ Give reasons. Acceleration, a = g = 9.8 m/s2 And Radius of the earth, Re = 6.4 × 106 m. Question 7. How much do you know about gravitation? % Variation in the weight of a body = % Change in g = 0.7%. MCQs on CBSE Class 9 Science Chapter- Gravitation are provided here with answers. Question 4. Molecules in air in the atmosphere are attracted by gravitational force of the earth. Question 1. Is weight a force? (a) No The way the world works is exciting. (Where Ve is the volume of the earth) If it does, why does the earth not move towards the apple? It is denoted by ‘g’. Zero. Because the value of acceleration due to gravity (g) on the moon’s surface is nearly l/6th to that of the surface of the earth. When hypothetically M becomes 4 M and R becomes $$\frac{R}{2}$$. We know from Newton’s second law of motion that the force is the product of mass and acceleration. the mass of body P = m1 Question 1. Calculate its speed after 2 s. Also find the speed with which the stone strikes the ground. New weight becomes 1.1 times. The accepted value of G is 6.67x 1CT-11 Nm 2 kg-2. Weight, W = mg, m = $$\frac{W}{g}$$, m = $$\frac{9.8}{9.8}$$ = 1 kg (3) or t = $$\frac{0.5}{9.8}$$ = 0.05 s. Question 11. Now, mass of the earth, Me = 6 × 1024 kg or F = G × $$\frac{m_{1} m_{2}}{r^{2}}$$ ……..(3) ⇒ Time of ascent = Time of descent. Physics: Multiple Choice Questions on Gravitation. Here, g = 1.67 ms-2, R = 1.74 × 106 m and G = 6.67 × 10-2 Nm2 kg-2, Question 2. This is because acceleration due to gravity is independent of the mass of the falling body. Acceleration, g = – 9.8 m/s2 = M + $$\frac{10}{100}$$M = M + $$\frac{M}{10}$$ = $$\frac{11M}{10}$$ = 1.1 M It is different at different places. and radius of the moon, Rm = 1740 km Question Answers, Page 134. Question 19. Question 1. At what place on the earth’s surface is the weight of a body minimum? or, v2 – 02 = 2(-10) × (-40) Question 3. 3. TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. Question 8. Will this ratio remain the same if (i) one of the objects is hollow and the other one is solid; and (ii) both of them are hollow, size remaining the same in each case? Question 4. (G = 6.67 × 1011 Nm2kg-2) The weight of the body on the moon is about one-sixth of its weight on the earth. A: 1 kg B: 9.8 kg C: 9.8 Kg-m/Sec 2 D: 9.8 N. Answer. or D = $$\frac{g R^{2}}{G \frac{4}{3} \pi R^{3}}=\frac{3 g}{4 \pi G R}$$, Question 6. Answer: Answer: The gravitational force is responsible for providing the necessary centripetal force which allows the earth to move around the sun at the defined path or orbit. The position of required point is at a distance of 4 m from mass of 3 kg. Question 18. Gravitation is the force of attraction between any two bodies while gravity refers to attraction between any body and the earth. Differences between g andG. If the earth attracts two objects with equal force, can we say that their masses must be equal? This solution contains questions, answers, images, step by step explanations of the complete Chapter 10 titled Gravitation of Science taught in class 9. Access Answers to NCERT Class 9 Science Chapter 10 – Gravitation ( All In text and Exercise Questions Solved) Exercise-10.1 Page: 134. ans F ∝ $$\frac{1}{r^{2}}$$ ..(2) ⇒ m1 = m2, Question 3. Become a part of our community of millions and ask any question that you do not find in our Gravitation Q&A library. Our online gravitation trivia quizzes can be adapted to suit your requirements for taking some of the top gravitation quizzes. Question 14. radius of the earth, Re = 6400 km It occurs only when a body is in a state of free fall under the effect of gravity alone. The force (F) of gravitational attraction on a body of mass m due to earth of mass M and radius R is given by Answer: Suppose the mass of the earth somehow increases by 10% without any change in its size. Why does a body orbiting in space possess zero weight with respect to a spaceship? The ‘G’ is a universal constant, i.e., its value is the same (i.e. [NCERT Exemplar] What will be its speed when it has fallen 100 m? Enter OTP. In case of free fall acceleration does not depend upon mass and size. (i) As v = u + gt We = $$\frac{G M_{e} m}{R_{e}^{2}}$$ …(2) Question 2. These Gravitation Objective Questions with Answers are important for competitive exams like JEE, NEET, AIIMS, JIPMER etc. Answer: Enjoy the videos and music you love, upload original content, and share it all with friends, family, and the world on YouTube. (e) What is the ball’s acceleration at point A? part1, Page 1 The value of ‘g’ at the equator of the earth is lesser than that at poles. Define acceleration due to gravity. Question 3. Gravitational force between moon and the earth keeps moon in uniform circular motion around the earth. Class 9 | Science | Chapter 10 |Gravitation| NCERT Solutions. […] The entire NCERT textbook questions have been solved by best teachers for you. (g) At which point does the bal 1 have the same speed as when it was thrown? Question 17. The moon will begin to move in a straight line in the direction in which it was moving at that instant because the circular motion of moon is due to centripetal force provided by the gravitational force of the earth. Thus, equation (3) becomes, ∴ W = $$\frac{G M m}{r^{2}}$$ or – 0.25 = -19.6 h A stone is dropped from the top of a 40 m high tower. What is the source of centripetal force that a planet requires to revolve around the sun? Find out the speed with which he threw the second stone. Question 5. Is the acceleration due to gravity acting on a freely falling body directly proportional to the (a) mass of the body? Question 1. = $$20 \sqrt{2}$$ms-1, Question 6. Free Question Bank for NEET Physics Gravitation. h = 1.27 cm Ask your doubt of gravitation and get answer from subject experts and students on TopperLearning. v = u + gt1 The earth attracts an apple. Zero. Then what will happen to your weight? Question 10. Yes. Asked by Umesh 1st December 2017 9:49 AM . For the second stone, Both stones will take the same time to reach the ground because the two stones fall from the same height. v = $$\sqrt{1960}$$m/s = 44.2 m/s. FQ = $$\frac{G \times M_{e} \times m_{2}}{R^{2}}$$ ……. It is the measure of inertia of the body. F = mg …(2) Why can one jump higher on the surface of the moon than on the earth? Its value also varies from one celestial body to another. A comprehensive database of gravitation quizzes online, test your knowledge with gravitation quiz questions. Using physics, you can calculate the gravitational force that is exerted on one object by another object. Answer: Why does a body reach the ground quicker at poles than at the equator when dropped from the same height? The time taken for a body is less if the acceleration due to gravity is more when the initial velocities and the distance travelled are the same. t2 = u/g …(2) Thus a big stone will fall with the same acceleration as a small stone. ∴ For the second stone, v2 = 2gs = 2 × 9.8 × 100 = 1960 Kerala Plus One Physics Chapter Wise Questions and Answers Chapter 8 Gravitation Plus One Physics Gravitation One Mark Questions and Answers Question 1. Question 16. Answer: Very Short Answer Type Questions. Upward motion Initial speed, u = 0.5 m/s The acceleration due to gravity does not depend upon the mass of the stone or body. Answer: Answer: Answer: Derive expression for force of attraction between two bodies and then define gravitational constant. The mass of the Sun is 2 x 10 30 kg and that of the Earth is 6 x 10 24 kg. At the poles. Explain why all of them do not fall into the earth just like an apple falling from a tree. Height of the building, h = ? G = F Answer: Answer: When M changes to new mass M’ Question 13. Similarly, the force of attraction between the earth and the body Q is given by Final speed, v = 0 Answer: What does a small value of G indicate? One second later, he throws another stone. (d) What is the ball’s acceleration at point C? OTP has been sent to your mobile number and is valid for one hour Answer: Answer: This law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of distance between them. Therefore, the packets fall slowly at equator in comparison to the poles. A ball is thrown up with a speed of 0.5 m/s. [NCERT Exemplar] Mass of the earth, Me = 6 × 1024 kg Question 20. (b) No. Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. Answer: Given, Mass of the Sun, M = 2 x 10 30 kg Free Question Bank for 11th Class Physics Gravitation Gravitation Conceptual Problems Question 1. ∴ 49 = 0 × t + $$\frac{1}{2}$$ × 9.8 × t2 On what factors does that force depend? (ii) How long will it take to reach that height? Free PDF download of Important Questions with solutions for CBSE Class 9 Science Chapter 10 - Gravitation prepared by expert Science teachers from latest edition of CBSE(NCERT) books. Answer: i.e., weight will increase by 10%. This hypothesis is not correct. Suppose gravity of earth suddenly becomes zero, then which direction will the moon begin to move if no other celestial body affects it? Answer: Both C and D; [(Kg-m/Sec 2) = N] Q.19 Weight of free fall object is. Question 7: Law of gravitation gives the gravitational force between (a) the earth and a point mass only That is, for the second stone, t = (3.16 – 1)s = 2.16s ⇒ t2 = $$\frac{98}{9.8}$$ = 10 They both hit the ground at the same time. It also implies that a body orbiting in space has zero weight with respect to a spaceship. QUESTION 6 (2002 EXAM) (a) Calculate the magnitude of the gravitational acceleration g at the Earth's surface, using Newton's second law and the law of universal gravitation. F ∝ $$\frac{m_{1} \times m_{2}}{r^{2}}$$ Calculate the average density of the earth in terms of g, G and R. Question 1. Answer. 1. Question 12. Answer: If a body of mass m is placed on the surface of moon, then weight of the body on the moon is Fp = $$\frac{G \times M_{e} \times m_{1}}{R^{2}}$$ …..(1) Initial velocity, u = 0 Let the mass, m3 = 0.5 kg be placed at a distance of ‘x’ m from m1, as shown in figure. Is the time taken by a body to rise to the highest point equal to the time taken to fall from the same height? Two planets of radii R 1 and R 2 have the same density. Get all questions and answers of Gravitation of MAHARASHTRA Class 10 Physics on TopperLearning. So, acceleration = $$\frac{\text { Force }}{\text { Mass }}=\frac{20}{1}$$ = 20 m/s2, Question 3. 0 = u – gt1 Question 5. As we know s = ut + $$\frac{1}{2}$$ gt2 Gravitation is the force of attraction that tends to draw together any two objects in the universe. Who formulated the universal law of gravitation? Question 15. v = 0 + gt2 Answer: Mention any four phenomena that the universal law of gravitation was able to explain. Prove that if a body is thrown vertically upward, the time of ascent is equal to the time of descent. Answer: Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. (f) What is the bal l’s acceleration at point B? (i) Original weight = $$\frac{G M m}{r^{2}}$$, where M is the mass of the earth. The solved question papers from chapter 08 Gravitation have all type of questions may be asked in annual exams such as VSA very short answer type questions, SA short answer type questions, LA long answer type questions, VBA value based questions and HOTS higher order thinking skill based questions. Here, initial velocity, u = 0 Question 4. Question 11. We know that F = $$\frac{G M m}{r^{2}}$$ as weight of a body is the force with which a body is attracted towards the earth, If the average distance between the Sun and the Earth is 1.5 x 10 11 m, calculate the force exerted by the Sun on the Earth and also by Earth on the Sun. The astronaut and the spaceship are orbiting with same acceleration hence, the body does not exert any force on the sides of the spaceship. When a body is thrown vertically upwards, what is its final velocity? How is gravitation different from gravity? Here, s = 100 m, u = 0 The weight will become 16 times. Acceleration in downward direction = g And the mass of body Q=m2 (b) time of fall of the body? A: mass of the object × gravitational acceleration B: Zero Draw areal velocity versus time graph for mars. (i) How high will it go before it begins to fall? Which stone would reach the ground first and why? NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12, Extra Questions for Class 9 Science Chapter 10 Gravitation. Question 2. Answer: Why? Assume that g = 10 m/s2 and that there is no air resistance. So, v2 = u2 + 2gs, or h = $$\frac{0.25}{19.6}$$ = 0.0127 m (c) At which point is the bal 1 at its maximum height? ∴ v = u If the radius of the moon is 1.74 × 106 m, calculate the mass of the moon. Answer: Its SI unit is the same as the SI unit of force, i.e., Newton (N). mass of the moon, Mm = 7.4 × 1022 kg It will remain the same on the moon, i.e., 9.8 kg. i.e., the second stone was thrown downward with a speed of 12.1 ms-1. Page No: 134. (f) Acceleration = 10 ms-2 Wm = $$\frac{G M_{m} m}{R_{m}^{2}}$$ …(1) Yes. Answer: Gravitational constant is numerically equal to the force of attraction between two masses of 1 kg that are separated by a distance of 1 m. (d) Acceleration = 10 ms-2 h2 = $$\frac{1}{2} g t_{2}^{2}$$, Thus, the packets will remain in air for longer time interval, when it is dropped at the equator. Justify your answer. i.e., weight will be reduced to one-fourth of the original. Question 2. Answer: $$\frac{G \times M e \times m_{1}}{R^{2}}=\frac{G \times M_{e} \times m_{2}}{R^{2}}$$ Solution: The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. Ratio will not change in either case because acceleration remains the same. For example, given the weight of, and distance between, two objects, you can calculate how large the force of gravity is between them. Register online for Science tuition on Vedantu.com to score more marks in your examination. Answer: [NCERT Exemplar] Take g = 9.8 m/s2. If the mass of a body is 9.8 kg on the earth, what would be its mass on the moon? Question 7. New mass, M’=M + 10% of M If the radius of the earth becomes twice of its original radius, then The earth attracts an apple. Question 1. u = 0 + gt2 Answer: Suppose the radius of the earth becomes twice of its present radius without any change in its mass, what will happen to your weight? When body is at a distance V from centre of the earth then g = $$\frac{G M}{r^{2}}$$. Weight of the same body on the earth’s surface will be Identical packets are dropped from two aeroplanes—one above the equator and other above the north pole, both at height h. Assuming all conditions to be identical, will those packets take same time to reach the surface of earth? Answer: A force of 20 N acts upon a body whose weight is 9.8 N. What is the mass of the body and how much is its acceleration? Practicing All Gravitation - IIT JEE Entrance Exam Questions and Answers in online helps you to improve your ability to attend the real time maths, chemistry, physics Entrance Exams. At the equator. Here are some practice questions that you can try. W = $$\frac{G M m}{(2 r)^{2}}$$ As u = 0, h1 = $$\frac{1}{2} g t_{1}^{2}$$ Do you agree with his hypothesis or not? GK Quiz on Gravitation How gravity works, what causes gravity, what is gravity made of, etc. Suppose the mass of the moon is Mm and its radius is Rm. On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. A student thought that two bricks tied together would fall faster than a single one under the action of gravity. Question 5. (b) At which point is the bal 1 stationary? Gravitational force. [NCERT Exemplar] Answer: Do fluids possess weight? Question 4. The two bricks like a single body, fall with the same speed to reach the ground at the same time in case of free fall. Answer The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force.The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Two bodies of masses 3 kg and 12 kg are placed at a distance 12 m. A third body of mass 0.5 kg is to be placed at such a point that the force acting on this body is zero. Acted upon by gravitation of MAHARASHTRA Class 10 Physics questions in detail Vedantu.com to score more in! Increases by 10 % without any change in its mass question and improve application skills preparing. Up with a speed of 12.1 ms-1 the acceleration due to gravity which... Is lesser than that at poles while gravity refers to attraction between any body and the distance between them of... Score more gravitation questions and answers in your examination to m2 motion of a body doubled! 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